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Get Full Access to Introductory Chemistry - 5 Edition - Chapter 14 - Problem 25q
Get Full Access to Introductory Chemistry - 5 Edition - Chapter 14 - Problem 25q

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# How is pOH defined? A change of 2.0 pOH units corresponds

ISBN: 9780321910295 34

## Solution for problem 25Q Chapter 14

Introductory Chemistry | 5th Edition

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Problem 25Q

How is pOH defined? A change of 2.0 pOH units corresponds to how much of a change in $$\left[\mathrm{OH}^-\right]$$?

Equation Transcription:

Text Transcription:

[OH^-]

Step-by-Step Solution:

Solution 25Q:

Step 1:

pOH is defined as the negative logarithm of of the hydroxide ion concentration. pOH is used to specify the basicity of a solution.

pOH = - log [OH-]------(1)

Step 2 of 3

Step 3 of 3

##### ISBN: 9780321910295

Introductory Chemistry was written by and is associated to the ISBN: 9780321910295. This full solution covers the following key subjects: change, pOH, much, defined, corresponds. This expansive textbook survival guide covers 19 chapters, and 2046 solutions. Since the solution to 25Q from 14 chapter was answered, more than 419 students have viewed the full step-by-step answer. The answer to “?How is pOH defined? A change of 2.0 pOH units corresponds to how much of a change in $$\left[\mathrm{OH}^-\right]$$?Equation Transcription:Text Transcription:[OH^-]” is broken down into a number of easy to follow steps, and 21 words. The full step-by-step solution to problem: 25Q from chapter: 14 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5.

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