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Ammonia and oxygen react to form nitrogen and
Chapter 6, Problem 53QP(choose chapter or problem)
Ammonia and oxygen react to form nitrogen and water.
\(4 \mathrm{NH}_{3}(\mathrm{~g})+3 \mathrm{O}_{2}(\mathrm{~g}) \longrightarrow 2 \mathrm{~N}_{2}(\mathrm{~g})+6 \mathrm{H}_{2} \mathrm{O}(\mathrm{g})\)
a. How many grams of \(O_2\) are needed to react with 13.6 g of \(\mathrm{NH}_{3}\)?
b. How many grams of \(N_2\) can be produced when 6.50 g of \(O_2\) reacts?
c. How many grams of water are formed from the reaction of 34.0 g of \(\mathrm{NH}_{3}\)?
Questions & Answers
QUESTION:
Ammonia and oxygen react to form nitrogen and water.
\(4 \mathrm{NH}_{3}(\mathrm{~g})+3 \mathrm{O}_{2}(\mathrm{~g}) \longrightarrow 2 \mathrm{~N}_{2}(\mathrm{~g})+6 \mathrm{H}_{2} \mathrm{O}(\mathrm{g})\)
a. How many grams of \(O_2\) are needed to react with 13.6 g of \(\mathrm{NH}_{3}\)?
b. How many grams of \(N_2\) can be produced when 6.50 g of \(O_2\) reacts?
c. How many grams of water are formed from the reaction of 34.0 g of \(\mathrm{NH}_{3}\)?
Step 1 of 3
The balanced equation can be given as follows:
\(4N{H_3}\left( g \right) + 3{O_2}\left( g \right) \to 2{N_2}\left( g \right) + 6{H_2}O\left( g \right)\)
The molar masses of ammonia, oxygen, nitrogen and water are 17 g/mol, 32 g/mol, 28 g/mol and 18 g/mol.
The equation has 4 moles of ammonia and 3 moles of oxygen reacting with 2 moles of nitrogen and 6 moles of water.
Hence, 68 g of ammonia reacts with 96 g of oxygen to generate 56 g of nitrogen and 108 g of water.
68 g of ammonia reacts with 96 g of oxygen.
The amount of oxygen for 13.6 g can be found as follows:
\({\rm{Amount of oxygen = }}\frac{{{\rm{13}}{\rm{.6g \times 96g}}}}{{{\rm{68g}}}}\)
\({\rm{Amount of oxygen = 19}}{\rm{.2g}}\)
Hence, the amount of oxygen for 13.6 g ammonia is 19.2 g.