×
Log in to StudySoup
Get Full Access to Chemistry - Textbook Survival Guide
Join StudySoup for FREE
Get Full Access to Chemistry - Textbook Survival Guide

Four solutions of unknown HCl concentration are titrated

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 47P Chapter 14

Introductory Chemistry | 5th Edition

  • Textbook Solutions
  • 2901 Step-by-step solutions solved by professors and subject experts
  • Get 24/7 help from StudySoup virtual teaching assistants
Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

4 5 1 393 Reviews
21
2
Problem 47P

Four solutions of unknown HCl concentration are titrated with solutions of NaOH. The following table lists the volume of each unknown HCl solution, the volume of NaOH solution required to reach the equivalence point, and the concentration of each NaOH solution. Calculate the concentration (in M) of the unknown HCl solution in each case.

HCl Volume (mL)

NaOH Volume (mL)

[NaOH] (M)

(a) 25.00 Ml

28.44 mL

0.1231 M

(b) 15.00 mL

21.22 mL

0.0972 M

(c) 20.00 mL

14.88 mL

0.1178 M

(d) 5.00 mL

6.88 mL

0.1325 M

Step-by-Step Solution:
Step 1 of 3

Solution: Here, we are going to calculate the concentration of the unknown HCl solution.

Step1:

Neutralisation reaction is the reaction between an acid and a base to give salt and water. The neutralization reaction in the given problem is:

                                NaOH(aq) + HCl(aq) →H2O(l) + NaCl(aq)

Here, 1 mole of HCl requires 1 mole of NaOH for complete neutralization.

Step2:

In titration calculations, the unknown concentration can be calculated by the following formula:

                        

Where, VA = volume of acid used

        VB = volume of base used

        MA = concentration of acid

        MB = concentration of base

        nA = no. of moles of acid in balanced equation for reaction

        nB = no. of moles of base in balanced equation for reaction

Step3:

 Given, VA = 25.00 mL

VB = 28.44 mL

MA = concentration of acid

MB = 0.1231 M

nA = 1

nB = 1

Substituting the values in the above equation, we get,

                        25 mL x MA = 28.44 mL x 0.1231 M

                                 MA = 3.500964 / 25 M

                                 MA = 0.14 M

Thus, concentration of the unknown HCl solution is 0.14 M.

Step4:...

Step 2 of 3

Chapter 14, Problem 47P is Solved
Step 3 of 3

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

Unlock Textbook Solution

Enter your email below to unlock your verified solution to:

Four solutions of unknown HCl concentration are titrated

×
Log in to StudySoup
Get Full Access to Chemistry - Textbook Survival Guide
Join StudySoup for FREE
Get Full Access to Chemistry - Textbook Survival Guide
×
Reset your password