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Solved: Four solutions of unknown HCl concentration are titrated with solutions of NaOH

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 47P Chapter 14

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 47P

Four solutions of unknown HCl concentration are titrated with solutions of NaOH. The following table lists the volume of each unknown HCl solution, the volume of NaOH solution required to reach the equivalence point, and the concentration of each NaOH solution. Calculate the concentration (in M) of the unknown HCl solution in each case.

HCI Volume (mL)

NaOH Volume (mL)

[NaOH] (M)

(a) 25.00 mL

     28.44 mL

0.1231 M

(b) 15.00 mL

     21.22 mL

0.0972 M

(c) 20.00 mL

     14.88 mL

0.1178 M

(d) 5.00 mL

     6.88 mL

0.1325 M

Step-by-Step Solution:

Step 1 of 6

Solution: Here, we are going to calculate the concentration of the unknown \(\mathrm{HCl}\) solution.

Neutralisation reaction is the reaction between an acid and a base to give salt and water. The neutralization reaction in the given problem is:

                                                  \(\mathrm{NaOH} \text { (aq) }+\mathrm{HCl} \text { (aq) } \rightarrow \mathrm{H}_{2} \mathrm{O} \text { (1) }+\mathrm{NaCl} \text { (aq) }\)

Here, 1 mole of \(\mathrm{HCl}\) requires 1 mole of \(\mathrm{NaOH}\) for complete neutralization.

 

Step 2 of 6

Chapter 14, Problem 47P is Solved
Step 3 of 6

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

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Solved: Four solutions of unknown HCl concentration are titrated with solutions of NaOH