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Solved: Nitric oxide (NO) reacts readily with chlorine gas
Chapter 10, Problem 81AE(choose chapter or problem)
Problem 81AE
Nitric oxide (NO) reacts readily with chlorine gas as follows:
2 NO(g) + Cl2(g) ⇌ 2 NOCl(g)
At 700 K, the equilibrium constant Kp for this reaction is 0.26. Predict the behavior of each of the following mixtures at this temperature and indicate whether or not the mixtures are at equilibrium. If not, state whether the mixture will need to produce more products or reactants to reach equilibrium.
(a) PNO = 0.15 atm, PCl2 = 0.31 atm, PNOCl = 0.11 atm
(b) PNO = 0.12 atm, PCl2 = 0.10 atm, PNOCl = 0.050 atm
(c) PNO = 0.15 atm, PCl2 = 0.20 atm, PNOCl = 5.10 × 10-3 atm
Questions & Answers
QUESTION:
Problem 81AE
Nitric oxide (NO) reacts readily with chlorine gas as follows:
2 NO(g) + Cl2(g) ⇌ 2 NOCl(g)
At 700 K, the equilibrium constant Kp for this reaction is 0.26. Predict the behavior of each of the following mixtures at this temperature and indicate whether or not the mixtures are at equilibrium. If not, state whether the mixture will need to produce more products or reactants to reach equilibrium.
(a) PNO = 0.15 atm, PCl2 = 0.31 atm, PNOCl = 0.11 atm
(b) PNO = 0.12 atm, PCl2 = 0.10 atm, PNOCl = 0.050 atm
(c) PNO = 0.15 atm, PCl2 = 0.20 atm, PNOCl = 5.10 × 10-3 atm
ANSWER:
Problem 81AE
Nitric oxide (NO) reacts readily with chlorine gas as follows:
At 700 K, the equilibrium constant for this reaction is 0.26 . Predict the behavior of each of the following mixtures at this temperature and indicate whether or not the mixtures are at equilibrium. If not, state whether the mixture will need to produce more products or reactants to reach equilibrium.
(a) PNO =0.15 atm , PCl2=0.31 atm , PNOCl =0.11 atm
(a) PNO = 0.15 atm, PC12 = 0.31 atm, PNOCl = 0.11 atm
(b) PNO = 0.12 atm, PC12 = 0.10 atm, PNOCl = 0.050 atm
(C) PNO = 0.15 atm, PCI2 = 0.20 atm, PNOCl =
Step by step solution
Step 1 of 3
a)
, and
Calculate the value of Q-
Q=1.734
Therefore, ‘Q’ is greater than thus the equilibrium should shift from right to left.
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