Solved: Nitric oxide (NO) reacts readily with chlorine gas

Chapter 10, Problem 81AE

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QUESTION:

Problem 81AE

Nitric oxide (NO) reacts readily with chlorine gas as follows:

2 NO(g) + Cl2(g) ⇌ 2 NOCl(g)

At 700 K, the equilibrium constant Kp for this reaction is 0.26. Predict the behavior of each of the following mixtures at this temperature and indicate whether or not the mixtures are at equilibrium. If not, state whether the mixture will need to produce more products or reactants to reach equilibrium.

(a) PNO = 0.15 atm, PCl2 = 0.31 atm, PNOCl = 0.11 atm

(b) PNO = 0.12 atm, PCl2 = 0.10 atm, PNOCl = 0.050 atm

(c) PNO = 0.15 atm, PCl2 = 0.20 atm, PNOCl = 5.10 × 10-3 atm

Questions & Answers

QUESTION:

Problem 81AE

Nitric oxide (NO) reacts readily with chlorine gas as follows:

2 NO(g) + Cl2(g) ⇌ 2 NOCl(g)

At 700 K, the equilibrium constant Kp for this reaction is 0.26. Predict the behavior of each of the following mixtures at this temperature and indicate whether or not the mixtures are at equilibrium. If not, state whether the mixture will need to produce more products or reactants to reach equilibrium.

(a) PNO = 0.15 atm, PCl2 = 0.31 atm, PNOCl = 0.11 atm

(b) PNO = 0.12 atm, PCl2 = 0.10 atm, PNOCl = 0.050 atm

(c) PNO = 0.15 atm, PCl2 = 0.20 atm, PNOCl = 5.10 × 10-3 atm

ANSWER:

Problem 81AE

Nitric oxide (NO) reacts readily with chlorine gas as follows:

                                     

At 700 K, the equilibrium constant  for this reaction is 0.26 . Predict the behavior of each of the following mixtures at this temperature and indicate whether or not the mixtures are at equilibrium. If not, state whether the mixture will need to produce more products or reactants to reach equilibrium.

(a) PNO =0.15 atm , PCl2=0.31 atm , PNOCl =0.11 atm

(a) PNO = 0.15 atm, PC12 = 0.31 atm, PNOCl = 0.11 atm

(b) PNO = 0.12 atm, PC12 = 0.10 atm, PNOCl = 0.050 atm

(C) PNO = 0.15 atm, PCI2 = 0.20 atm, PNOCl =

                                                      Step by step solution

Step 1 of 3

a) 

,  and

Calculate the value of Q-

Q=1.734

Therefore,  ‘Q’ is greater than  thus the equilibrium should shift from right to left.

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