What is the amount of energy involved in each of the

Solution 35QPStep 1 of 3:The goal of the problem is to calculate the amount of energy involved in given conditions.We know, the formula to calculate specific heat: Specific heat = This can be rewritten to calculate heat energy as: Heat = mass Tspecific heata. Given:Mass of water = 25 g.Initial temperature (Ti ) = 15 °CFinal temperature (Tf ) = 25 °CEnergy in calories =First, let’s calculate T: T = Final temperature (Tf) - Initial temperature (Ti ) = 25 °C - 15 °C = 10 °CNow, let’s calculate the heat energy:Specific heat of water = 4.184 J/g °CTherefore, the heat energy will be: = 25 g 10 °C 4.184 J/g °C = 1.04103 JNow, let’s convert energy in joules to calories: 1 cal = 4.184 JSo, the conversion factor is = 1.04103 J = 248.56 cal.________________