Calculate [H3O+] given [OH ] in each aqueous solution and classify each solution as

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

ISBN: 9780321910295 34

Solution for problem 66P Chapter 14

Introductory Chemistry | 5th Edition

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Problem 66P

Calculate [H3O+] given [OH ] in each aqueous solution and classify each solution as acidic or basic.

(a) [OH−] = 2.1 × 10−11 M

(b) [OH−] = 7.5 × 10−9 M

(d) [OH−] = 1.0 × 10−2 M

Step-by-Step Solution:

Problem 66P

Calculate [H3O+] given [OH ] in each aqueous solution and classify each solution as acidic or basic.

(a)

(b)

(c)

(d)

Step by step solution

Step 1 of 4

The concentrated ions decreases when ions concentration increases.

This is because the dissociation constant or ionization constant has to remain constant.

Hence, The dissociation constant for water is given as follows.

(a)

From the given

Let’s calculate the

We have to use the ionic product constant .

...........................(1)

Rearrange the formula (1) is as follows.

....................................(2)

Now, substitute the values in the formula, then we get

Therefore,the solution is acidic.

______________________________________________________________________________

Step 2 of 4

Chapter 14, Problem 66P is Solved

Step 3 of 4

Textbook: Introductory Chemistry

Edition: 5

Author: Nivaldo J Tro

ISBN: 9780321910295

Introductory Chemistry was written by and is associated to the ISBN: 9780321910295. The full step-by-step solution to problem: 66P from chapter: 14 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. The answer to “Calculate [H3O+] given [OH ] in each aqueous solution and classify each solution as acidic or basic.(a) [OH?] = 2.1 × 10?11 M(b) [OH?] = 7.5 × 10?9 M(c) [OH?] = 2.1 × 10?4 M(d) [OH?] = 1.0 × 10?2 M” is broken down into a number of easy to follow steps, and 41 words. This full solution covers the following key subjects: solution, calculate, basic, aqueous, classify. This expansive textbook survival guide covers 19 chapters, and 2046 solutions. Since the solution to 66P from 14 chapter was answered, more than 333 students have viewed the full step-by-step answer. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5.