Solution Found!
Calculate the pH of each solution.(a) [OH?] = 1.9 × 10?7 M(b) [OH?] = 2.6 × 10?8 M(c)
Chapter 14, Problem 73P(choose chapter or problem)
Calculate the pH of each solution.
(a) \(\mathrm{[OH^-]=1.9 \times 10^{-7} ~M}\)
(b) \(\mathrm{[OH^-]=2.6 \times 10^{-8} ~M}\)
(c) \(\mathrm{[OH^-]=7.2 \times 10^{-11} ~M}\)
(d) \(\mathrm{[OH^-]=9.5 \times 10^{-2} ~M}\)
Equation Transcription:
Text Transcription:
[OH^-]=1.9 x 10^{-7} M
[OH^-]=2.6 x 10^{-8} M
[OH^-]=7.2 x 10^{-11} M
[OH^-]=9.5 x 10^{-2} M
Questions & Answers
QUESTION:
Calculate the pH of each solution.
(a) \(\mathrm{[OH^-]=1.9 \times 10^{-7} ~M}\)
(b) \(\mathrm{[OH^-]=2.6 \times 10^{-8} ~M}\)
(c) \(\mathrm{[OH^-]=7.2 \times 10^{-11} ~M}\)
(d) \(\mathrm{[OH^-]=9.5 \times 10^{-2} ~M}\)
Equation Transcription:
Text Transcription:
[OH^-]=1.9 x 10^{-7} M
[OH^-]=2.6 x 10^{-8} M
[OH^-]=7.2 x 10^{-11} M
[OH^-]=9.5 x 10^{-2} M
ANSWER:
Solution 73P :
Step 1:
Here, we have to pH of each solution :
pOH is the measure of concentration of hydroxide ion (OH-) in the solution. It is used to measure the alkalinity of a solution.
To calculate the pOH of a solution we should know the concentration of the hydroxide ion in moles per liter, i.e the molarity of the solution.
pOH is calculated using the expression:
pOH = - log [OH-]