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Determine the pOH of each solution and classify it as

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 79P Chapter 14

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 79P

Determine the pOH of each solution and classify it as acidic, basic, or neutral.

(a) [OH−] = 1.5 × 10−9 M

(b) [OH−] = 7.0 × 10−5 M

(c) [OH−] = 1.0 × 10−7 M

(d) [OH−] = 8.8 × 10−3 M

Step-by-Step Solution:
Step 1 of 3

Solution 79P:

Here, we are going to calculate the pOH of each solution and identify whether the reaction is acidic, basic and neutral.

We know,  the ion product constant Kw for water is

Kw =[H3O+][OH-] = 1x10-14

pH + pOH =14

And pOH =  - log[OH- ] and pH = - log[H+ ]

(a) [OH−] = 1.5 × 10−9 M

We know,

pOH =  - log[OH- ]

        = -log(1.5 × 10−9 )

          = 9 -log1.5

          = 9 -0.176

        = 8.82

And pH = 14-pOH = 14-8.82 =5.17

Therefore, pH < 7

The pOH of the solution is 8.82

and the solution is acidic in nature.

(b) [OH−] = 7.0 × 10−5 M

We know,

pOH =  - log[OH- ]

        = -log(7.0 × 10−5 )

          = 5 -log 7.0

          = 5...

Step 2 of 3

Chapter 14, Problem 79P is Solved
Step 3 of 3

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. Introductory Chemistry was written by and is associated to the ISBN: 9780321910295. Since the solution to 79P from 14 chapter was answered, more than 360 students have viewed the full step-by-step answer. This full solution covers the following key subjects: acidic, basic, classify, determine, neutral. This expansive textbook survival guide covers 19 chapters, and 2045 solutions. The full step-by-step solution to problem: 79P from chapter: 14 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. The answer to “Determine the pOH of each solution and classify it as acidic, basic, or neutral.(a) [OH?] = 1.5 × 10?9 M(b) [OH?] = 7.0 × 10?5 M(c) [OH?] = 1.0 × 10?7 M(d) [OH?] = 8.8 × 10?3 M” is broken down into a number of easy to follow steps, and 38 words.

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