How much 0.100 M HCl is required to completely neutralize 20.0 mL of 0.250 M NaOH?

Step 1:

How much 0.100 M HCl is required to completely neutralize 20.0 mL of 0.250 M NaOH?

Given :

Molarity of HCl(Hydrochloric acid)(M1) = 0.100 M

Molarity of NaOH(sodium hydroxide) (M2) = 0.250 M

Volume of NaOH(V2)= 20.0 mL

Volume of HCl to neutralize NaOH (V1) = ?

Let’s write the chemical reaction for the given scenario :

HCl +NaOHNaCl+H20

We know the formula to calculate the molarity of the diluted solution, :

M1V1 = M2V2

Where, M1 and V1 = Molarity and volume of initial concentrated solution.

M2 and V2 = Molarity and volume of final diluted solution.

Using the above formula we calculate the volume of HCl to neutralize NaOH.

We have to calculate V1, hence the formula becomes :

V1 =

Volume of NaOH is in mL, so let’s convert to L :

1 L = 1000 mL

Therefore, 20.0 mL in L will be :

= 20 mL

= 0.020 L