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# How much 0.100 M HCl is required to completely neutralize ISBN: 9780321910295 34

## Solution for problem 89P Chapter 14

Introductory Chemistry | 5th Edition

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Problem 89P

How much 0.100 M HCl is required to completely neutralize 20.0 mL of 0.250 M NaOH?

Step-by-Step Solution:

Step 1:

How much 0.100 M HCl is required to completely neutralize 20.0 mL of 0.250 M NaOH?

Given :

Molarity of HCl(Hydrochloric acid)(M1) = 0.100 M

Molarity of NaOH(sodium hydroxide) (M2) = 0.250 M

Volume of NaOH(V2)= 20.0 mL

Volume of HCl to neutralize NaOH (V1) = ?

Let’s write the chemical reaction for the given scenario :

HCl +NaOH NaCl+H20

We know the formula to calculate the molarity of the diluted solution, :

M1V1 = M2V2

Where, M1 and V1 = Molarity and volume of initial concentrated solution.

M2 and V2 = Molarity and volume of final diluted solution.

Using the above formula we calculate the volume of HCl to neutralize NaOH.

We have to calculate V1, hence the formula becomes :

V1 = Volume of NaOH is in mL, so let’s convert to L :

1 L = 1000 mL

Therefore, 20.0 mL in L will be :

= 20 mL  = 0.020 L

Step 2 of 2

##### ISBN: 9780321910295

Introductory Chemistry was written by and is associated to the ISBN: 9780321910295. Since the solution to 89P from 14 chapter was answered, more than 310 students have viewed the full step-by-step answer. This full solution covers the following key subjects: completely, HCL, much, naoh, neutralize. This expansive textbook survival guide covers 19 chapters, and 2045 solutions. The answer to “How much 0.100 M HCl is required to completely neutralize 20.0 mL of 0.250 M NaOH?” is broken down into a number of easy to follow steps, and 16 words. The full step-by-step solution to problem: 89P from chapter: 14 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5.

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