Calculate the molar mass of each of the following: (6.5)a.

Chapter 6, Problem 104AQP

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QUESTION:

Calculate the molar mass of each of the following: (6.5)a. Mg(HCO3)2, magnesium hydrogen carbonateb. Au(OH)3, gold(III) hydroxide, used in gold platingc. C18H34O2, oleic acid from olive oil

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QUESTION:

Calculate the molar mass of each of the following: (6.5)a. Mg(HCO3)2, magnesium hydrogen carbonateb. Au(OH)3, gold(III) hydroxide, used in gold platingc. C18H34O2, oleic acid from olive oil

ANSWER:

Solution 104 AQPHere, we are calculating the molar mass each of the following.To calculate the molar mass of each element by its subscript in the formula.Step 1 of 3a.Mg(HCO3)2First, let’s write the molar mass of each element in the Mg(HCO3)2Molar mass of Magnesium = Molar mass of Hydrogen = Molar mass of Carbon = Molar mass of Oxygen = Let’s multiply each molar mass by the number of moles (subscript) in the formula.Grams from 1 mole of Magnesium 1 mole Magnesium = 24.3 g of Mg.Grams from 2 mole of Hydrogen 2 mole of Hydrogen = 2.0 g of HGrams from 2 moles of Carbon 2 moles of Carbon = 24.0 g of CGrams from 6 moles of Oxygen 6 mole of Oxygen = 96.0 g of O.Let’s calculate the molar mass of Mg(HCO3)2by adding molar masses of elements 1 mole of Mg = 24.3 g 2 moles of H = 2.0g 2 moles of C = 24.0g 6 moles of O = 96.0 g________________________________________ Molar mass of Mg(HCO3)2 = 146.3 gTherefore, Molar mass of Mg(HCO3)2 is 146.3 g______________________________________________________________________________

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