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Solved: What is the minimum volume of 3.0 M HBr required to completely dissolve 15.0 g

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 92P Chapter 14

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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1
Problem 92P

What is the minimum volume of 3.0 M HBr required to completely dissolve 15.0 g of potassium metal?

Step-by-Step Solution:

Solution 92P :

Step 1:

Given :

Molarity of HBr (Hydrobromic acid) = 3.0 M

Amount of K(Potassium) metal = 15.0 g

Volume of HBr to completely dissolve Mg = ?

Let’s write the chemical equation for the given scenario :

                        2 K(s) + 2HBr →  2 KBr + H2(g)

From the above reaction, we see the ratio of reactants is 2 : 2.

Now, let’s find the number of moles of K and HBr :

                Number of moles(n) =

Molar mass of K = 39.0983 g/mol.

Therefore, n =

         = 0.3836 moles.                                   

We are not given the mass of HBr, but from the reaction, we know that the ratio of K and HBr is 2 : 2. Hence, the moles of HBr will be 0.3836 moles.

Step 2 of 2

Chapter 14, Problem 92P is Solved
Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

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Solved: What is the minimum volume of 3.0 M HBr required to completely dissolve 15.0 g