A 0.105-g sample of a diprotic acid of unknown molar mass is dissolved in water and titrated with 0.1288 M NaOH. The equivalence point is reached after adding 15.2 mL of base. What is the molar mass of the unknown acid?
Here, we need to calculate the molar mass of the unknown acid.
Strength of NaOH = 0.1288 M = 0.1288 mol/L
Volume of NaOH = 15.2 ml = 0.0152 L
Amount of NaOH required = 0.1288 mol/L x 0.0152 L = 0.00196 mol