Problem 96P
A 0.105-g sample of a diprotic acid of unknown molar mass is dissolved in water and titrated with 0.1288 M NaOH. The equivalence point is reached after adding 15.2 mL of base. What is the molar mass of the unknown acid?
Solution 96P:
Here, we need to calculate the molar mass of the unknown acid.
Step 1:
Strength of NaOH = 0.1288 M = 0.1288 mol/L
Volume of NaOH = 15.2 ml = 0.0152 L
Amount of NaOH required = 0.1288 mol/L x 0.0152 L = 0.00196 mol