×
Log in to StudySoup
Get Full Access to Introductory Chemistry - 5 Edition - Chapter 14 - Problem 96p
Join StudySoup for FREE
Get Full Access to Introductory Chemistry - 5 Edition - Chapter 14 - Problem 96p

Already have an account? Login here
×
Reset your password

Solved: A 0.105-g sample of a diprotic acid of unknown molar mass is dissolved in water

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 96P Chapter 14

Introductory Chemistry | 5th Edition

  • Textbook Solutions
  • 2901 Step-by-step solutions solved by professors and subject experts
  • Get 24/7 help from StudySoup virtual teaching assistants
Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

4 5 1 371 Reviews
28
0
Problem 96P

A 0.105-g sample of a diprotic acid of unknown molar mass is dissolved in water and titrated with 0.1288 M NaOH. The equivalence point is reached after adding 15.2 mL of base. What is the molar mass of the unknown acid?

Step-by-Step Solution:

Solution 96P:

Here, we need to calculate the molar mass of the unknown acid.

Step 1:

Strength of NaOH = 0.1288 M = 0.1288 mol/L

Volume of NaOH = 15.2 ml = 0.0152 L

Amount of NaOH required = 0.1288 mol/L x 0.0152 L = 0.00196 mol

Step 2 of 3

Chapter 14, Problem 96P is Solved
Step 3 of 3

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

Other solutions

People also purchased

Related chapters

Unlock Textbook Solution

Enter your email below to unlock your verified solution to:

Solved: A 0.105-g sample of a diprotic acid of unknown molar mass is dissolved in water