×
Log in to StudySoup
Get Full Access to Introductory Chemistry - 5 Edition - Chapter 14 - Problem 101p
Join StudySoup for FREE
Get Full Access to Introductory Chemistry - 5 Edition - Chapter 14 - Problem 101p

Already have an account? Login here
×
Reset your password

Complete the table. (The first row is completed for you.)[H3O+][OH?]pOHpHAcidic or

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 101P Chapter 14

Introductory Chemistry | 5th Edition

  • Textbook Solutions
  • 2901 Step-by-step solutions solved by professors and subject experts
  • Get 24/7 help from StudySoup virtual teaching assistants
Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

4 5 1 398 Reviews
12
2
Problem 101P

Problem 101P

Complete the table. (The first row is completed for you.)

[H3O+]

[OH−]

pOH

pH

Acidic or Basic

1.0 × 10−4

1.0 × 10−10

10.00

4.00

Acidic

5.5 × 10−3

________

________

________

________

________

3.2 × 10−6

________

________

________

4.8 × 10−9

________

________

________

________

________

________

________

7.55

________

Step-by-Step Solution:
Step 1 of 3

Solution 101P: Here, we are going to complete the given table.

Step1:

pH is the negative logarithm to base 10 of hydrogen ion concentration whereas pOH is the negative logarithm to base 10 of hydroxyl ion concentration, i.e.,

 pOH =  - log[OH- ] and pH = - log[H+ ]

And pH + pOH =14

We can distinguish acidic, neutral and basic aqueous solutions by the relative values of their pH

                        Acidic: pH < 7

                        Neutral: pH = 7

                        Basic: pH > 7

Step2:

[H3O+]

[OH-]

pOH

pH

Acidic or Basic

1.0 x 10-4

1.0 x 10-10

10.00

4.00

Acidic

5.5 x 10-3

1.82 x 10-12

11.74

2.26

Acidic

3.13 x 10-9

3.2 x 10-6

5.495

8.505

Basic

4.8 x 10-9

2.08 x 10-6

5.681

8.319

Basic

2.82 x 10-8

3.55 x 10-7

6.45

7.55

Basic

  1. Given, [H3O+] = 5.5 x 10-3

Therefore, pH = - log[H3O+ ]

= - log (5.5 x 10-3)

= - log 5.5 - log 10-3

= - 0.740 + 3

= 2.26

Therefore, pOH = 14 - pH

                  = 14 - 2.26

                  = 11.74

pOH =   - log[OH- ]

Therefore, [OH- ] = 10-pOH 

                     = 10-11.74

                    = 1.82 x 10-12

Since, pH < 7, therefore the solution is acidic.

     b)        Given, [OH-] = 3.2 x 10-6

Therefore, pOH = - log[OH-]

= - log (3.2 x 10-6)

= - log 3.2 - log 10-6

= - 0.505 + 6

= 5.495

Therefore, pH = 14 - pOH

                  = 14 - 5.495

                  = 8.505

pH =   - log[H3O+]

Therefore, [H3O+] = 10-pH 

                     = 10-8.505

                    = 3.13 x 10-9

Since, pH > 7, therefore the solution is basic.

   c)        Given, [H3O+] = 4.8 x 10-9

Therefore, pH = - log[H3O+ ]

= - log (4.8 x 10-9)

= - log 4.8 - log 10-9

= - 0.681 + 9

= 8.319

Therefore, pOH = 14 - pH

                  = 14 - 8.319

                  = 5.681

pOH =   - log[OH- ]

Therefore, [OH- ] = 10-pOH 

                     = 10-5.681

                    = 2.08 x 10-6

Since, pH > 7, therefore the solution is basic.

    d)        Given, pH = 7.55

pH =   - log[H3O+]

Therefore, [H3O+] = 10-pH 

                     = 10-7.55

                    = 2.82 x 10-8

pOH = 14 - pH

                = 14 - 7.55

                = 6.45

pOH =   - log[OH- ]

Step 2 of 3

Chapter 14, Problem 101P is Solved
Step 3 of 3

Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

Since the solution to 101P from 14 chapter was answered, more than 379 students have viewed the full step-by-step answer. The answer to “Complete the table. (The first row is completed for you.)[H3O+][OH?]pOHpHAcidic or Basic1.0 × 10?41.0 × 10?1010.004.00Acidic5.5 × 10?3________________________________________3.2 × 10?6________________________4.8 × 10?9________________________________________________________7.55________” is broken down into a number of easy to follow steps, and 22 words. This full solution covers the following key subjects: acidi, completed, complete, basic, pOH. This expansive textbook survival guide covers 19 chapters, and 2046 solutions. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. The full step-by-step solution to problem: 101P from chapter: 14 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. Introductory Chemistry was written by and is associated to the ISBN: 9780321910295.

Other solutions

People also purchased

Related chapters

Unlock Textbook Solution

Enter your email below to unlock your verified solution to:

Complete the table. (The first row is completed for you.)[H3O+][OH?]pOHpHAcidic or