Problem 30Q

Write an expression for the solubility-product constant of A2B(s). Assume that an ion of B has a charge of 2– (that is, B2−).

Solution:

We have to write the expression of solubility product for A2B, where the charge B is -2 i.e B2-

The equation can be written as ,A2B 2A+ + B2-

Kc = [A+]2 [B2-]

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[A2B]

Kc [A2B] = [A+]2 [B2-]

Ksp = [A+]2 [B2-]