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A saturated solution of MgF2 has [Mg2+] = 2.6 ×

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 81P Chapter 15

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 81P

A saturated solution of MgF2 has [Mg2+] = 2.6 × l(T4Mand[F−] = 5.2 × 10−4M. What is the value of Ksp for MgF2?

Step-by-Step Solution:

Solution 81P :

Step 1:

Given :

[Mg2+] = 2.6 × l0-4 M

[F-] = 5.2 × 10-4 M

Ksp for MgF2 = ?

Ksp is the solubility product constant. It is the equilibrium constant of a solid substance that is dissolved in aqueous solution. It represents the level at which a solute dissolves in solution. It changes with the temperature. Ksp is the mathematical product of the concentrations of the ion dissolved raised to the power of their stoichiometric coefficients.

For the reaction :

                aA(s)  ⇋  cC(aq) + dD(aq)

The formula of Ksp is :

                Ksp =

Step 2 of 2

Chapter 15, Problem 81P is Solved
Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

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