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A saturated solution of PbCl2 has [Cl?] = 2.86 × 10?2 M. What is the concentration of
Chapter 15, Problem 84P(choose chapter or problem)
QUESTION:
A saturated solution of \(\mathrm {PbCl_2}\) has \(\mathrm {[Cl^-]=2.86 \times 10^{-2}~ M}\). What is the concentration of \(\mathrm {Pb^{2+}}\)?
Equation Transcription:
Text Transcription:
PbCl_2
[Cl^-]=2.86 x 10^{-2} M
Pb^{2+}
Questions & Answers
QUESTION:
A saturated solution of \(\mathrm {PbCl_2}\) has \(\mathrm {[Cl^-]=2.86 \times 10^{-2}~ M}\). What is the concentration of \(\mathrm {Pb^{2+}}\)?
Equation Transcription:
Text Transcription:
PbCl_2
[Cl^-]=2.86 x 10^{-2} M
Pb^{2+}
ANSWER:
Solution:
Step 1
The concentration of [Cl-] in a saturated solution of PbCl2 = 2.86 × 10−2 M.
We have to calculate the concentration of Pb2+