Solution Found!

A saturated solution of PbCl2 has [Cl?] = 2.86 × 10?2 M. What is the concentration of

Chapter 15, Problem 84P

(choose chapter or problem)

Get Unlimited Answers
QUESTION:

A saturated solution of \(\mathrm {PbCl_2}\) has \(\mathrm {[Cl^-]=2.86 \times 10^{-2}~ M}\). What is the concentration of \(\mathrm {Pb^{2+}}\)?

Equation Transcription:

Text Transcription:

PbCl_2

[Cl^-]=2.86 x 10^{-2} M

Pb^{2+}

Questions & Answers

QUESTION:

A saturated solution of \(\mathrm {PbCl_2}\) has \(\mathrm {[Cl^-]=2.86 \times 10^{-2}~ M}\). What is the concentration of \(\mathrm {Pb^{2+}}\)?

Equation Transcription:

Text Transcription:

PbCl_2

[Cl^-]=2.86 x 10^{-2} M

Pb^{2+}

ANSWER:

Solution:

Step 1

The concentration of [Cl-] in a saturated solution of PbCl2 = 2.86 × 10−2 M.

We have to calculate the concentration of Pb2+

Add to cart


Study Tools You Might Need

Not The Solution You Need? Search for Your Answer Here:

×

Login

Login or Sign up for access to all of our study tools and educational content!

Forgot password?
Register Now

×

Register

Sign up for access to all content on our site!

Or login if you already have an account

×

Reset password

If you have an active account we’ll send you an e-mail for password recovery

Or login if you have your password back