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Get Full Access to Introductory Chemistry - 5 Edition - Chapter 15 - Problem 88p
Get Full Access to Introductory Chemistry - 5 Edition - Chapter 15 - Problem 88p

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Calculate the molar solubility of CuI (Ksp = 1.27 ×

ISBN: 9780321910295 34

Solution for problem 88P Chapter 15

Introductory Chemistry | 5th Edition

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Problem 88P

Calculate the molar solubility of CuI (Ksp = 1.27 × 10−12).

Step-by-Step Solution:
Step 1 of 3

Solution 88P:

Consider the equation

CuI.(s) ⇆ Cu+(aq) + I-(aq)

Let us consider the molar solubility of CuI (s) is  “ S” mol/L.

Thus,

Solubility product = [Cu+(aq)][ I-(aq)]

Ksp = [Cu+(aq)][ I-(aq)]  ------(1)

We know

Solubility product Ksp for CuI is 1.27 × 10−12

Therefore, from equation (1)

1.27 × 10−12  = S. S

S2 =1.27 × 10−12

= (1.27 × 10−12   )½  = 1.127  x 10-6 M

Thus, the molar solubility of CuI is 1.127  x 10-6 M.

Step 2 of 3

Step 3 of 3

ISBN: 9780321910295

Introductory Chemistry was written by and is associated to the ISBN: 9780321910295. The full step-by-step solution to problem: 88P from chapter: 15 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. Since the solution to 88P from 15 chapter was answered, more than 558 students have viewed the full step-by-step answer. The answer to “Calculate the molar solubility of CuI (Ksp = 1.27 × 10?12).” is broken down into a number of easy to follow steps, and 11 words. This full solution covers the following key subjects: calculate, cui, Molar, solubility. This expansive textbook survival guide covers 19 chapters, and 2046 solutions. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5.

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Calculate the molar solubility of CuI (Ksp = 1.27 ×