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Calculate the molar solubility of FeCO3. How many grams of

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 98P Chapter 15

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 98P

Calculate the molar solubility of FeCO3. How many grams of FeCO3 are present in 15.0 L of a saturated FeCO3 solution?

Step-by-Step Solution:

Solution 98P :

Step 1:

Given :

Volume of saturated FeCO3 solution = 15.0 L

Grams of  FeCO3 present in solution(Molar solubility) = ?

FeCO3 dissociates as :

        FeCO3(s) → Fe2+ (aq) + CO32- (aq)

So, Ksp will be :

                Ksp = [] []

To solve this problem, we need the solubility product, i.e Ksp for FeCO3. Assuming that the solution is at ambient temperature (25 oC), the value of the Ksp as 3.1310-11

Now, Let’s consider ‘x’ = [] and []

Therefore, Ksp = x²

     (3.1310-11) = x²

     x =

        = 5.59410-6 M

Hence,  [] and []  = 5.59410-6 M . i.e Concentration of saturated solution of FeCO3 = 5.59410-6 M.

Step 2 of 2

Chapter 15, Problem 98P is Solved
Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

Introductory Chemistry was written by and is associated to the ISBN: 9780321910295. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. Since the solution to 98P from 15 chapter was answered, more than 258 students have viewed the full step-by-step answer. The full step-by-step solution to problem: 98P from chapter: 15 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. This full solution covers the following key subjects: feco, Present, grams, Molar, calculate. This expansive textbook survival guide covers 19 chapters, and 2045 solutions. The answer to “Calculate the molar solubility of FeCO3. How many grams of FeCO3 are present in 15.0 L of a saturated FeCO3 solution?” is broken down into a number of easy to follow steps, and 21 words.

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