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Solved: Calculate the molar solubility of FeCO3. How many grams of FeCO3 are present in

Chapter 15, Problem 98P

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QUESTION:

Calculate the molar solubility of \(\mathrm {FeCO_3}\). How many grams of \(\mathrm {FeCO_3}\) are present in 15.0 L of a saturated \(\mathrm {FeCO_3}\) solution?

Equation Transcription:

Text Transcription:

FeCO_3

Questions & Answers

QUESTION:

Calculate the molar solubility of \(\mathrm {FeCO_3}\). How many grams of \(\mathrm {FeCO_3}\) are present in 15.0 L of a saturated \(\mathrm {FeCO_3}\) solution?

Equation Transcription:

Text Transcription:

FeCO_3

ANSWER:

Solution 98P :

Step 1:

Given :

Volume of saturated FeCO3 solution = 15.0 L

Grams of  FeCO3 present in solution(Molar solubility) = ?

FeCO3 dissociates as :

        FeCO3(s) → Fe2+ (aq) + CO32- (aq)

So, Ksp will be :

                Ksp = [] []

To solve this problem, we need the solubility product, i.e Ksp for FeCO3. Assuming that the solution is at ambient temperature (25 oC), the value of the Ksp as 3.1310-11

Now, Let’s consider ‘x’ = [] and []

Therefore, Ksp = x²

     (3.1310-11) = x²

     x =

        = 5.59410-6 M

Hence,  [] and []  = 5.59410-6 M . i.e Concentration of saturated solution of FeCO3 = 5.59410-6 M.

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