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Solved: Calculate the molar solubility of FeCO3. How many grams of FeCO3 are present in
Chapter 15, Problem 98P(choose chapter or problem)
Calculate the molar solubility of \(\mathrm {FeCO_3}\). How many grams of \(\mathrm {FeCO_3}\) are present in 15.0 L of a saturated \(\mathrm {FeCO_3}\) solution?
Equation Transcription:
Text Transcription:
FeCO_3
Questions & Answers
QUESTION:
Calculate the molar solubility of \(\mathrm {FeCO_3}\). How many grams of \(\mathrm {FeCO_3}\) are present in 15.0 L of a saturated \(\mathrm {FeCO_3}\) solution?
Equation Transcription:
Text Transcription:
FeCO_3
ANSWER:Solution 98P :
Step 1:
Given :
Volume of saturated FeCO3 solution = 15.0 L
Grams of FeCO3 present in solution(Molar solubility) = ?
FeCO3 dissociates as :
FeCO3(s) → Fe2+ (aq) + CO32- (aq)
So, Ksp will be :
Ksp = [] []
To solve this problem, we need the solubility product, i.e Ksp for FeCO3. Assuming that the solution is at ambient temperature (25 oC), the value of the Ksp as 3.1310-11
Now, Let’s consider ‘x’ = [] and []
Therefore, Ksp = x²
(3.1310-11) = x²
x =
= 5.59410-6 M
Hence, [] and [] = 5.59410-6 M . i.e Concentration of saturated solution of FeCO3 = 5.59410-6 M.