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For each redox reaction, identify the substance being oxidized, the substance being

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 44P Chapter 16

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 44P

For each redox reaction, identify the substance being oxidized, the substance being reduced, the oxidizing agent, and the reducing agent.

(a) \(\mathrm{H}_{2}(g)+\mathrm{I}_{2}(g) \longrightarrow 2~ \mathrm{HI}(g)\)

(b) \(\mathrm{CO}(g)+\mathrm{H}_{2}(g) \longrightarrow \mathrm{C}(s)+\mathrm{H}_{2} \mathrm{O}(g)\)

(c) \(2~ \mathrm{Al}(s)+6~ \mathrm{H}^{+}(a q) \longrightarrow 2~ \mathrm{Al}^{3+}(a q)+3~ \mathrm{H}_{2}(g)\)

Equation Transcription:

Text Transcription:

H_2(g)+I_2(g) rightarrow 2 HI(g)

CO(g)+H_2(g) rightarrow C(s)+H_2O(g)

2 Al(s)+6 H^+(aq) rightarrow 2 Al^3+(aq)+3 H_2(g)

Step-by-Step Solution:

Solution 44P :

Step 1:

An oxidizing agent is a chemical specie that removes one or more oxygen atom of other chemical substances in the redox chemical reaction and thus it gains electrons in a chemical reaction.

A reducing agent is a chemical specie that donates electrons to another chemical substance in a redox chemical reaction and thus it loses electrons in a chemical reaction.

Step 2 of 2

Chapter 16, Problem 44P is Solved
Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

The answer to “?For each redox reaction, identify the substance being oxidized, the substance being reduced, the oxidizing agent, and the reducing agent.(a) \(\mathrm{H}_{2}(g)+\mathrm{I}_{2}(g) \longrightarrow 2~ \mathrm{HI}(g)\)(b) \(\mathrm{CO}(g)+\mathrm{H}_{2}(g) \longrightarrow \mathrm{C}(s)+\mathrm{H}_{2} \mathrm{O}(g)\)(c) \(2~ \mathrm{Al}(s)+6~ \mathrm{H}^{+}(a q) \longrightarrow 2~ \mathrm{Al}^{3+}(a q)+3~ \mathrm{H}_{2}(g)\)Equation Transcription:Text Transcription:H_2(g)+I_2(g) rightarrow 2 HI(g)CO(g)+H_2(g) rightarrow C(s)+H_2O(g)2 Al(s)+6 H^+(aq) rightarrow 2 Al^3+(aq)+3 H_2(g)” is broken down into a number of easy to follow steps, and 50 words. This full solution covers the following key subjects: agent, Being, substance, oxidized, oxidizing. This expansive textbook survival guide covers 19 chapters, and 2046 solutions. Since the solution to 44P from 16 chapter was answered, more than 312 students have viewed the full step-by-step answer. The full step-by-step solution to problem: 44P from chapter: 16 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM. Introductory Chemistry was written by and is associated to the ISBN: 9780321910295. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5.

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For each redox reaction, identify the substance being oxidized, the substance being