Problem 62P

Write a nuclear equation for the beta decay of each nuclide.

(a) Pb-211

(b) Tl-207

(c) Th-234

(d) Pa-234

Solution 62P:

Here, we are going to write a nuclear equation for the beta decay of each nuclide.

Beta decay (defined as

Neutron → proton + emitted electron

The nuclear equation is

01n 11p + -10e

or 01n 11p +

Thus, when an atom emits particle, the neutron of the nucleus is converted to proton which increases the atomic number by 1.

(a) Pb-211

The nuclear equation for the beta decay ( -10e)

21182 Pb 21183 Bi + -10e

(b) Tl-207

The nuclear equation for the beta decay ( -10e)

20781Tl 20782 Pb + -10e

(c) Th-234

The nuclear equation for the beta decay ( -10e)

23490Th 23491 Pa + -10e

(d) Pa-234

The nuclear equation for the beta decay ( -10e)

23491 Pa 23492U + -10e