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Get Full Access to Introductory Chemistry - 5 Edition - Chapter 17 - Problem 64p
Get Full Access to Introductory Chemistry - 5 Edition - Chapter 17 - Problem 64p

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# Write a nuclear equation for positron emission by each nuclide.(a) Co-55(b) Na-22(c)

ISBN: 9780321910295 34

## Solution for problem 64P Chapter 17

Introductory Chemistry | 5th Edition

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Problem 64P

Problem 64P

Write a nuclear equation for positron emission by each nuclide.

(a)  Co-55

(b) Na-22

(c) F-18

Step-by-Step Solution:
Step 1 of 3

Solution 64P:

Here, we are going to write nuclear equations for positron emission by each nuclide.

Step1:

Positron emission is similar to beta emission(splitting of a neutron into a proton and an accompanying electron.), but in this case, a proton becomes a neutron and an anti-matter electron, or antielectron. The latter is also called a positron because, although it resembles an electron in most ways, it has a positive charge.

P  →  n  +  e+

In nuclear equations for positron emission, the electron is written as either 𝛃+, e or e.

In positron emission, the radioactive nuclide changes into a different element, with an atomic number that is lower by 1 but the same mass number.

Step2:

1. Co-55

The atomic number of Co is 27. So, when Co-55 undergoes positron emission, a daughter nuclei with atomic number 26(Fe) is formed. The nuclear equation is:

Co   →  Fe   +   e

b)        Na-22

The atomic number of Na is 11. So, when Na-22 undergoes positron emission, a daughter nuclei with atomic number 10(Ne) is formed. The nuclear equation is:

Na   →  Ne   +   e

c)        F-18

The atomic number of F is 9. So, when F-18 undergoes positron emission, a daughter nuclei with atomic number 8(O) is formed. The nuclear equation is:

F   →  O   +   e

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Step 2 of 3

Step 3 of 3

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