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# A mammoth skeleton has a carbon-14 content of 12.50% of ## Problem 82P Chapter 17

Introductory Chemistry | 5th Edition

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Problem 82P

A mammoth skeleton has a carbon-14 content of 12.50% of that found in living organisms. When did the mammoth live?

Step-by-Step Solution:
Step 1 of 3

Solution 82P:

Here, we are going to calculate the time of death of the mammoth.

Step1:

The time taken for one-half of a sample to disappear is called its half life(t1/2). The half life period of carbon-14 is 5730 years

Now, we know that,

t1/2 = k = = = 1.209x 10-4 yr-1

Step2:

Let the carbon-14 content in living organisms be 100

Therefore, carbon-14 content in the mammoth skeleton = 12.50

Again, from kinetics, the rate constant, k is given by-

k = log , where, [R]o = initial concentration

[R]...

Step 2 of 3

Step 3 of 3

##### ISBN: 9780321910295

Since the solution to 82P from 17 chapter was answered, more than 833 students have viewed the full step-by-step answer. Introductory Chemistry was written by and is associated to the ISBN: 9780321910295. The answer to “A mammoth skeleton has a carbon-14 content of 12.50% of that found in living organisms. When did the mammoth live?” is broken down into a number of easy to follow steps, and 20 words. This full solution covers the following key subjects: mammoth, live, DID, found, content. This expansive textbook survival guide covers 19 chapters, and 2045 solutions. This textbook survival guide was created for the textbook: Introductory Chemistry, edition: 5. The full step-by-step solution to problem: 82P from chapter: 17 was answered by , our top Chemistry solution expert on 05/06/17, 06:45PM.

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