The fission of U-235 produces 3.2 × 10−11J/atom. How much energy does it produce per mole of U-235? Per kilogram of U-235?
Solution 91P :
Energy produced in fission of U-235 = 3.2 × 10-11 J/atom
Energy produced per mole of U-235 = ?
Energy produced per Kg of U-235 = ?
Before calculating energy per mole, we need to know the mass of Uranium in the fission reaction. So let’s calculate the mass from Einstein's famous equation:
E = mc2
where, E = energy
m = mass converted to energy
c = velocity of light = 3108 m/s
Formula to find mass becomes :
= 3.5510-28 Kg
Now, that we know the mass of Uranium that was used in the fission reaction, let’s calculate the energy released per mole :
We know, 1 mole of any particle contains avogadro’s number of particles(6.0231023 particles)
E = 3.5510-28 Kg (3108 m/s)2 6.0231023
= 1.9 × 1013 joules.
Hence the energy produced per mole in the fission reaction of U-235 is 1.9 × 1013 joules.