Solution Found!

Solved: Po-218 is an alpha emitter with a half-life of 3.0 minutes. If a sample contains

Chapter 17, Problem 94P

(choose chapter or problem)

Get Unlimited Answers! Check out our subscriptions

Questions & Answers

QUESTION:

Problem 94P

Po-218 is an alpha emitter with a half-life of 3.0 minutes. If a sample contains 55 mg of Po-218, how many alpha emissions occur in 6.0 minutes?

ANSWER:

Solution:

Step 1

  If the half life is 3.0 min, after 6.0 minutes the number of lifetimes will be

6.0 / 3.0= 2.

The final mass of Po will be:

M(Po-f) = Mo ( 1 / 2n = 55 )

1 / 22 = 55

 55 / 4 = 13.75 mg = 0.01375 g

Add to cart

Become a subscriber and get unlimited answers!


Study Tools You Might Need

×

Login

Login or Sign up for access to all of our study tools and educational content!

Forgot password?
Register Now

×

Register

Sign up for access to all content on our site!

Or login if you already have an account

×

Reset password

If you have an active account we’ll send you an e-mail for password recovery

Or login if you have your password back