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Bi-210 is a beta emitter with a half-life of 5.0 days. If

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 93P Chapter 17

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 93P

Bi-210 is a beta emitter with a half-life of 5.0 days. If a sample contains 1.2 g of Bi-210, how many beta emissions occur in 5.0 days?

Step-by-Step Solution:

Solution 93P :

Step 1 :

Given :

Half life of Bi -210 (t1/2) = 5.0 days.

Mass of Bi-210 = 1.2 g.

Number of beta emissions occur in 5 days = ?

Given:

We know the equation for first order rate equation of kinetics of radioactive delay:

ln () = - k t

Where, A = amount of radioisotope remaining after time "t" has passed.

 Ao= initial amount of radioisotope at the beginning of the period

 K = rate constant for the radioisotope

t1/2 =  for first order reaction

Therefore, k =   

      k =  

                 = 0.1386

Step 2:

Now, let’s calculate the amount of Bi-210 remaining after the decay has occurred :

ln A - ln A0 = -k t

ln A =

        =

 ln A = -0.5775

A = e-0.5775

A = 2.14 g

Step 3 of 3

Chapter 17, Problem 93P is Solved
Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

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