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Identify the parent nuclides and daughter nuclides in the

Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro ISBN: 9780321910295 34

Solution for problem 20Q Chapter 17

Introductory Chemistry | 5th Edition

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Introductory Chemistry | 5th Edition | ISBN: 9780321910295 | Authors: Nivaldo J Tro

Introductory Chemistry | 5th Edition

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Problem 20Q

Identify the parent nuclides and daughter nuclides in the nuclear equation. Which kind of radioactive decay is involved?

Step-by-Step Solution:

Solution 20Q :

Step 1:

Here, we have to identify the parent nuclides and daughter nuclides in the nuclear equation and state the kind of radioactive decay is involved.

In the chemical equation, the original atom is called the parent nuclide and the products are called as the daughter nuclides. When an element emits an alpha particle, the number of protons in its nucleus changes, transforming it into a different element.

Step 2 :

        Here, the parent nuclide is Pa(Protactinium) and the daughter nuclides are Ac(Actinium) and He(Helium).

Like chemical equations, the nuclear equation should also be balanced.  A balanced nuclear equation is an nuclear equation where the sum of the atomic numbers on both sides of a nuclear equation must be equal, and the sum of the mass numbers(which is the top number in the notation) on both sides must also be equal.

We can note here that :

On Left Side :                                 On Right Side :

----------------------------------                ------------------------------------------

Sum of mass numbers = 231                 Sum of mass numbers = 227 + 4 = 231

Sum of atomic numbers = 91                Sum of atomic numbers = 89 + 2 = 91

Step 3 of 3

Chapter 17, Problem 20Q is Solved
Textbook: Introductory Chemistry
Edition: 5
Author: Nivaldo J Tro
ISBN: 9780321910295

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