Solution Found!
At 30 oC, the second-order rate constant for the reaction
Chapter 5, Problem 28P(choose chapter or problem)
Problem 28P
At 30 oC, the second-order rate constant for the reaction of methyl chloride and HO- is 1.0 x 10-5 M-1 s-1.
a. What is the rate of the reaction when [CH3Cl] = 0.10 M and [HO-] = 0.10 M?
b. If the concentration of methyl chloride is decreased to 0.010 M, what will be the effect on
1. the rate of the reaction?
2. the rate constant for the reaction?
Questions & Answers
QUESTION:
Problem 28P
At 30 oC, the second-order rate constant for the reaction of methyl chloride and HO- is 1.0 x 10-5 M-1 s-1.
a. What is the rate of the reaction when [CH3Cl] = 0.10 M and [HO-] = 0.10 M?
b. If the concentration of methyl chloride is decreased to 0.010 M, what will be the effect on
1. the rate of the reaction?
2. the rate constant for the reaction?
ANSWER:
Solution:
Step 1
(a)Here we will have to calculate the rate of the reaction.
In this question it has been given that the second-order rate constant for the reaction of methyl chloride and HO- is K = 1.0 10-5 M-1 s-1
[CH3Cl] = 0.10 M and [HO-] = 0.10 M
Hence the rate of the reaction can be calculated as,
r = K [CH3Cl] [OH-]
r = (1.0
10-5 M-1 s-1)
(0.1)M
(0.1)M
= 1.0 10-7M s-1
Thus the rate constant is found to be 1.0 10-7M s-1.