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Solved: a. What is the equilibrium constant for a reaction
Chapter 5, Problem 55P(choose chapter or problem)
Problem 55P
a. What is the equilibrium constant for a reaction that is carried out at 25 oC (298 K) with ΔHo = 20 kcal/mol and ΔSo = 5.0 x 10-2 kcal mol-1 K-1?
b. What is the equilibrium constant for the same reaction carried out at 125 oC?
Questions & Answers
QUESTION:
Problem 55P
a. What is the equilibrium constant for a reaction that is carried out at 25 oC (298 K) with ΔHo = 20 kcal/mol and ΔSo = 5.0 x 10-2 kcal mol-1 K-1?
b. What is the equilibrium constant for the same reaction carried out at 125 oC?
ANSWER:
Solution:
Here we have to found out the equilibrium constant.
Step 1
a . Given:
ΔHo = 20 kcal/mol
ΔSo = 5.0 10-2 kcal mol-1 K-1
Temperature (T) = 25 oC (298 K)
The equilibrium constant Keq can be calculated as follows,
Go = - RT lnKeq
Now, we will have to calculate Go, from the given data by using the formula
Go = ΔHo - T ΔSo
= 20Kcal/mol - (298 K0.05 Kcal mol-1K-1)
= (20-14.9) = 5.1 kcal/mol
Thus, the free energy is 5.1 kcal/mol.