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Solved: a. What is the equilibrium constant for a reaction

Chapter 5, Problem 55P

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QUESTION:

Problem 55P

a. What is the equilibrium constant for a reaction that is carried out at 25 oC (298 K) with ΔHo = 20 kcal/mol and ΔSo = 5.0 x 10-2 kcal mol-1 K-1?

b. What is the equilibrium constant for the same reaction carried out at 125 oC?

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QUESTION:

Problem 55P

a. What is the equilibrium constant for a reaction that is carried out at 25 oC (298 K) with ΔHo = 20 kcal/mol and ΔSo = 5.0 x 10-2 kcal mol-1 K-1?

b. What is the equilibrium constant for the same reaction carried out at 125 oC?

ANSWER:

Solution:

Here we have to found out the equilibrium constant.

Step 1

a . Given:

ΔHo = 20 kcal/mol

ΔSo = 5.0  10-2 kcal mol-1 K-1 

Temperature (T) = 25 oC (298 K)

The equilibrium constant Keq can be calculated as follows,

Go = - RT lnKeq

Now, we will have to calculate Go, from the given data by using the formula

Go = ΔHo - T ΔSo

         = 20Kcal/mol - (298 K0.05 Kcal mol-1K-1)

         = (20-14.9) = 5.1 kcal/mol

Thus, the free energy is 5.1 kcal/mol.

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