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Get Full Access to Conceptual Physics - 12 Edition - Chapter 3 - Problem 19rq
Get Full Access to Conceptual Physics - 12 Edition - Chapter 3 - Problem 19rq

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# What is the gain in speed per second for a freely falling ISBN: 9780321909107 29

## Solution for problem 19RQ Chapter 3

Conceptual Physics | 12th Edition

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Problem 19RQ

What is the gain in speed per second for a freely falling object?

Step-by-Step Solution:

Solution 19RQ Introduction For a freely falling object, the acceleration will be same since there is no external force is applied on it. The only force is gravitational force which is acting on the body. The acceleration due to gravity is a constant and it is represented as “g”. Step 1 According to the equation of motion. The equation for the velocity in free fall would be, v = u + at Where, u - initial velocity a - acceleration t - time taken At initial condition, t = 0 and u = 0 t = 0 then v 10. If t = 1 second, v =2 + gt a = g since the acceleration is acceleration due to gravity. v2= 0 + g × 1 seconds = g m/s Therefore, the change in velocity would be, v - v = g m/s - 0 m/s = g m/s 2 1 v3= 0 + 2 g = 2g m/s So, v3 v2 2g - g = g m/s So, the gain in speed in each second would be g m/s.

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##### ISBN: 9780321909107

Conceptual Physics was written by and is associated to the ISBN: 9780321909107. The answer to “What is the gain in speed per second for a freely falling object?” is broken down into a number of easy to follow steps, and 13 words. The full step-by-step solution to problem: 19RQ from chapter: 3 was answered by , our top Physics solution expert on 04/03/17, 08:01AM. This full solution covers the following key subjects: falling, freely, gain, Object, speed. This expansive textbook survival guide covers 45 chapters, and 4650 solutions. This textbook survival guide was created for the textbook: Conceptual Physics, edition: 12. Since the solution to 19RQ from 3 chapter was answered, more than 361 students have viewed the full step-by-step answer.

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