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Chapter 10, Problem 41P

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QUESTION:

For each of the following reactions, draw the major elimination product; if the product can exist as stereoisomers, indicate which stereoisomer is obtained in greater yield.

a. (R)-2-bromohexane + high concentration of \(\mathrm{CH}_{3} \mathrm{O}^{-}\)

b. (R)-3-bromo-3-methylhexane + \(\mathrm{CH}_{3} \mathrm{OH}\)

c. trans-1-chloro-2-methylcyclohexane + high concentration of \(\mathrm{CH}_{3} \mathrm{O}^{-}\)

d. trans-1-chloro-3-methylcyclohexane + high concentration of \(\mathrm{CH}_{3} \mathrm{O}^{-}\)

e. 3-bromo-3-methylpentane + high concentration of \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{O}^{-}\)

f. 3-bromo-3-methylpentane + \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}\)

Questions & Answers

QUESTION:

For each of the following reactions, draw the major elimination product; if the product can exist as stereoisomers, indicate which stereoisomer is obtained in greater yield.

a. (R)-2-bromohexane + high concentration of \(\mathrm{CH}_{3} \mathrm{O}^{-}\)

b. (R)-3-bromo-3-methylhexane + \(\mathrm{CH}_{3} \mathrm{OH}\)

c. trans-1-chloro-2-methylcyclohexane + high concentration of \(\mathrm{CH}_{3} \mathrm{O}^{-}\)

d. trans-1-chloro-3-methylcyclohexane + high concentration of \(\mathrm{CH}_{3} \mathrm{O}^{-}\)

e. 3-bromo-3-methylpentane + high concentration of \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{O}^{-}\)

f. 3-bromo-3-methylpentane + \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}\)

ANSWER:

Solution 41P

Step 1 of 6

(a)

Methoxide ion is a strong base, which favors reaction. Here two types of -hydrogens are present and there is a chance of formation of two products, 1-hexene and 2-hexene. But only one product 2-hexene is formed due to its participation in conjugation. According to Saytzeff’s rule highly substituted alkenes are more stable than less substituted alkenes.

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