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Solved: The 1H NMR spectra of three isomers with molecular
Chapter 15, Problem 58P(choose chapter or problem)
The \({ }^{I} H\ N M R\) spectra of three isomers with molecular formula \(\mathrm{C}_{7} \mathrm{H}_{14} \mathrm{O}\) are shown here. Which isomer produces which spectrum?
Equation Transcription:
Text Transcription:
^I H NMR
C_7 H_14 O
Questions & Answers
QUESTION:
The \({ }^{I} H\ N M R\) spectra of three isomers with molecular formula \(\mathrm{C}_{7} \mathrm{H}_{14} \mathrm{O}\) are shown here. Which isomer produces which spectrum?
Equation Transcription:
Text Transcription:
^I H NMR
C_7 H_14 O
ANSWER:
Solution 58P
(a) From the 1H NMR spectrum, the 9 protons give only one signal at 0.94 ppm because of this reason the three methyl groups are bonded to one carbon.
The 3 protons give one signal at 2.13 ppm because of this reason the methyl group is bonded to carbonyl group. The 2 protons give one signal at 2.37 ppm because of this reason the methylene group is bonded to carbonyl group and tertiary butyl carbon.
Therefore, the isomer, 4,4-dimethyl-2-pentanone produces the below spectrum.