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Why was a deuterated compound used in the preceding

Chapter 28, Problem 14P

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QUESTION:

Problem 14P

Why was a deuterated compound used in the preceding example?

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QUESTION:

Problem 14P

Why was a deuterated compound used in the preceding example?

ANSWER:

Solution 14P

Step 1 of 2

The bond dissociation energy of C-H bond is higher than the “C-D”bond. Hence C-H bond not easily rearranges to another position. Due to the lown bond dissociation energy of C-D. It easily migrates to another position.

This is the reason to use the deuterated compound used in the reaction.

i.e.,

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