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Principles of General Chemistry | 2nd Edition | ISBN: 9780073511085 | Authors: Martin S. Silberberg
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Solved: A rock is 5.0% by mass fayalite (Fe2Si04), 7.0% by

Chapter 1, Problem 102

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QUESTION: Problem 102P

A rock is 5.0% by mass fayalite (Fe2Si04), 7.0% by mass forsterite (Mg2Si04), and the remainder silicon dioxide. What is the mass percent of each element in the rock?

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QUESTION: Problem 102P

A rock is 5.0% by mass fayalite (Fe2Si04), 7.0% by mass forsterite (Mg2Si04), and the remainder silicon dioxide. What is the mass percent of each element in the rock?

ANSWER:

Solution 102P

Here, we are calculate the percentage of each element in the fayalite,forsterite and silicon dioxide.

Step 1 of 13

First, let’s calculate the molar mass of fayalite.

Molecular formula of fayalite - Fe2SiO4.

Atomic mass of Fe = 2 x 55.85 amu = 111.70 amu

Atomic mass of S  = 1 x 28.09 amu  = 28.09 amu

Atomic mass of O = 4 x 16.00 amu =  64.00 amu

                                                           __________

Formula mass of Fayalite                  203.79 amu

                                                          __________

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