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The iodine molecule can be photodissociated into iodine
Chapter 7, Problem 89E(choose chapter or problem)
The iodine molecule can be photodissociated into iodine atoms in the gas phase with light of wavelengths shorter than about 792 nm. A 100.0 mL glass tube contains 55.7 mtorr of gaseous iodine at 25.0 °C . What minimum amount of light energy must be absorbed by the iodine in the tube to dissociate 15.0% of the molecules?
Questions & Answers
QUESTION:
The iodine molecule can be photodissociated into iodine atoms in the gas phase with light of wavelengths shorter than about 792 nm. A 100.0 mL glass tube contains 55.7 mtorr of gaseous iodine at 25.0 °C . What minimum amount of light energy must be absorbed by the iodine in the tube to dissociate 15.0% of the molecules?
ANSWER:Problem 89EThe iodine molecule can be photodissociated into iodine atoms in the gas phase withlight of wavelengths shorter than about 792 nm. A 100.0 mL glass tube contains 55.7mtorr of gaseous iodine at . What minimum amount of light energy must beabsorbed by the iodine in the tube to dissociate 15.0% of the molecules Step by step solutionStep 1 of 4From the given,Volume “V” = 100.0 mLLet’s convert volume from mL's to L. 1L = 1000 mLPressure “P” = 55.7 mtorrLet’s convert pressure from mtorr to atm.1 torr = 1000 m torr1 atm = 760 torrTemperature T= 25.0°C =(25.0+273)K = 298 K