The iodine molecule can be photodissociated into iodine

Chapter 7, Problem 89E

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QUESTION:

The iodine molecule can be photodissociated into iodine atoms in the gas phase with light of wavelengths shorter than about 792 nm. A 100.0 mL glass tube contains 55.7 mtorr of gaseous iodine at 25.0 °C . What minimum amount of light energy must be absorbed by the iodine in the tube to dissociate 15.0% of the molecules?

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QUESTION:

The iodine molecule can be photodissociated into iodine atoms in the gas phase with light of wavelengths shorter than about 792 nm. A 100.0 mL glass tube contains 55.7 mtorr of gaseous iodine at 25.0 °C . What minimum amount of light energy must be absorbed by the iodine in the tube to dissociate 15.0% of the molecules?

ANSWER:

Problem 89EThe iodine molecule can be photodissociated into iodine atoms in the gas phase withlight of wavelengths shorter than about 792 nm. A 100.0 mL glass tube contains 55.7mtorr of gaseous iodine at . What minimum amount of light energy must beabsorbed by the iodine in the tube to dissociate 15.0% of the molecules Step by step solutionStep 1 of 4From the given,Volume “V” = 100.0 mLLet’s convert volume from mL's to L. 1L = 1000 mLPressure “P” = 55.7 mtorrLet’s convert pressure from mtorr to atm.1 torr = 1000 m torr1 atm = 760 torrTemperature T= 25.0°C =(25.0+273)K = 298 K

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