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Release a single molecule in an evacuated region and it

Conceptual Physics | 12th Edition | ISBN: 9780321909107 | Authors: Paul G. Hewitt ISBN: 9780321909107 29

Solution for problem 32E Chapter 16

Conceptual Physics | 12th Edition

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Conceptual Physics | 12th Edition | ISBN: 9780321909107 | Authors: Paul G. Hewitt

Conceptual Physics | 12th Edition

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Problem 32E

Release a single molecule in an evacuated region and it will fall as fast as, and no differently from, a baseball released in the same region. Explain.

Step-by-Step Solution:

Solution 32E Step 1: Consider the mass of the molecule as “m”. If it is allowed to fall freely in an evacuated region, the only force experiencing is the gravitational force. 2 According to Newton’s universal law of gravitation, F = GMm/r Where, G - Gravitational constant M - Mass of earth (if the object is attracted by earth) m - mass of the molecule r - Distance between the earth and the molecule But we know that, force, F = ma from Newton’s 2nd law of motion. Where “m” is the mass of the molecule and “a” acceleration of the molecule under the influence of the force. So, replacing ‘F’ as ‘ma’ in the equation for gravitational force we get, ma = GMm/r 2 ‘m’ will cancel out on both sides and we get, a = GM/r which is a constant. So, the acceleration here is nothing but acceleration due to gravity and it will be a constant for earth. If we repeat the same process by using the mass of a baseball, it will not be changed and it is a constant. The acceleration due to gravity is represented by using the letter ‘g’. Since the acceleration is a constant, it does not depend on the mass of the falling object. If two objects are released from same height, both of them will reach the ground at same time. But, there is a possibility for the frictional force due to air. Actually the air resistance influences the free fall of objects with different masses. Conclusion: In this case, since the region is evacuated, the molecule and baseball released from the same height will hit the ground at same time since the acceleration due to gravity is same.

Step 2 of 1

Chapter 16, Problem 32E is Solved
Textbook: Conceptual Physics
Edition: 12
Author: Paul G. Hewitt
ISBN: 9780321909107

The full step-by-step solution to problem: 32E from chapter: 16 was answered by , our top Physics solution expert on 04/03/17, 08:01AM. This full solution covers the following key subjects: region, fast, evacuated, explain, Fall. This expansive textbook survival guide covers 45 chapters, and 4650 solutions. Since the solution to 32E from 16 chapter was answered, more than 496 students have viewed the full step-by-step answer. The answer to “Release a single molecule in an evacuated region and it will fall as fast as, and no differently from, a baseball released in the same region. Explain.” is broken down into a number of easy to follow steps, and 27 words. This textbook survival guide was created for the textbook: Conceptual Physics, edition: 12. Conceptual Physics was written by and is associated to the ISBN: 9780321909107.

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Release a single molecule in an evacuated region and it