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Chemistry: A Molecular Approach | 3rd Edition | ISBN: 9780321809247 | Authors: Nivaldo J. Tro
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Without doing any calculations, determine which solution

Chapter 15, Problem 157E

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QUESTION:

Without doing any calculations, determine which solution in each pair is more acidic.

a. 0.0100 M in HCl and 0.0100 M in KOH

b. 0.0100 M in HF and 0.0100 M in KBr

c. 0.0100 M in NH4Cl and 0.0100 M in CH3NH3Br

d. 0.100 M in NaCN and 0.100 M in CaCl2

Questions & Answers

QUESTION:

Without doing any calculations, determine which solution in each pair is more acidic.

a. 0.0100 M in HCl and 0.0100 M in KOH

b. 0.0100 M in HF and 0.0100 M in KBr

c. 0.0100 M in NH4Cl and 0.0100 M in CH3NH3Br

d. 0.100 M in NaCN and 0.100 M in CaCl2

ANSWER:

Problem 157E

Without doing any calculations, determine which solution in each pair is more acidic.

a. 0.0100 M in HCl and 0.0100 M in KOH

b. 0.0100 M in HF and 0.0100 M in KBr

c. 0.0100 M in   and 0.0100 M in  

d. 0.100 M in NaCN and 0.100 M in  

        

                                                              Step by Step Solution

Step 1 of 4

(a)

 0.0100 M in HCl and 0.0100 M in KOH

HCl is a strong acid and KOH is a strong base.They reacted to each other to form a neutral solution.

Hence, it is not an acidic solution.

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