Find the mass of 0°C ice that 10 g of 100°C steam will completely melt.
Solution 3P Introduction We have to first calculate the energy released by 100°C steam to become water of 100°C. The we can calculate the mass of the ice that can be melt using this amount of energy. Solution Step 1 The heat released by the condensation of steam is given by Q steam m steam steam Here m is the mass and L is the latent heat of the steam. steam steam Now we have m steam 10 g L steam 540 cal/g So we have Q = (10 g)(540 cal) = 5400 cal stem Step 2 Now in the above step, the steam will become 100°C water. Now the temperature of this water will also change to 0°C. Heat released in this process is givn by Q = m c T water water water water Where m is the mass of the water, c is the specific heat of the water, and T is the water water water temperature change in the water. We know that m = m = 10 g water steam cwater= 1 cal/g°C And T water (100°C 0°C) = 100°C Using this values we have Q = (10 g)(1 cal/g°C)(100°C) = 1000 cal water Hence the total heat released is Q = Q steam Q water= (5400 cal) + (1000 cal) = 6400 cal