Locate the state of R-410a at 30 psia, −20 F. Indicate in both the P–v and T–v diagrams the location of the nearest states listed in Table F.10.

Solution 139EUP

Step 1 of 3:

Our aim is to draw the P-v and T-v diagrams of the refrigerant R-410a using the data given in table F.10.

The given pressure P = 30 psia

The given temperature T = -20 F

From the table F.10.1 and F.10.2

The saturated temperature for the given pressure Tsat = 15.15 F

The saturated pressure for given temperature Psat = 13.009 psia