Locate the state of R-410a at 30 psia, −20 F. Indicate in both the P–v and T–v diagrams the location of the nearest states listed in Table F.10.
Step 1 of 3:
Our aim is to draw the P-v and T-v diagrams of the refrigerant R-410a using the data given in table F.10.
The given pressure P = 30 psia
The given temperature T = -20 F
From the table F.10.1 and F.10.2
The saturated temperature for the given pressure Tsat = 15.15 F
The saturated pressure for given temperature Psat = 13.009 psia
Textbook: Fundamentals of Thermodynamcs
Author: Claus Borgnakke, Richard E. Sonntag
This full solution covers the following key subjects: psia, SAT, LBM, btu, vapor. This expansive textbook survival guide covers 7 chapters, and 1462 solutions. Since the solution to 139EUP from 2 chapter was answered, more than 259 students have viewed the full step-by-step answer. Fundamentals of Thermodynamcs was written by and is associated to the ISBN: 9781118131992. The full step-by-step solution to problem: 139EUP from chapter: 2 was answered by , our top Engineering and Tech solution expert on 08/03/17, 05:05AM. This textbook survival guide was created for the textbook: Fundamentals of Thermodynamcs , edition: 8. The answer to “?Locate the state of R-410a at 30 psia, ?20 F. Indicate in both the P–v and T–v diagrams the location of the nearest states listed in Table F.10.” is broken down into a number of easy to follow steps, and 28 words.