Solution Found!
Consider a ball rolling around in a circular path on the
Chapter 28, Problem 92TAE(choose chapter or problem)
Consider a ball rolling around in a circular path on the inner surface of a cone. The weight of the ball is shown by the vector W. Without friction, only one other force acts on the ball—a normal force. (a) Draw in the vector for the normal force. (The length of the vector depends on the next step, b.) (b) Using the parallelogram rule, show that the resultant of the two vectors is along
Questions & Answers
QUESTION:
Consider a ball rolling around in a circular path on the inner surface of a cone. The weight of the ball is shown by the vector W. Without friction, only one other force acts on the ball—a normal force. (a) Draw in the vector for the normal force. (The length of the vector depends on the next step, b.) (b) Using the parallelogram rule, show that the resultant of the two vectors is along
ANSWER:
Step 1 of 3
With the ball being on a study circular path (there is no friction) we know that resultant force has to lie on the plane of the circular path. This also means that the resultant force is also the centripetal force.
Since the resultant force has to be in the plane of the circular path we know that vertically our vector of normal force has to be the same length as the vector of weight. This will mean that the resultant force will be in the plane of the circular path. Since the vector of normal force is diagonal because it has to be perpendicular to the side of the cone, the vector of the normal force is by default then larger than the vector of weight.