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Answer: Laplace transforms A powerful tool in solving
Chapter 7, Problem 79E(choose chapter or problem)
Laplace transforms A powerful tool in solving problems in engineering and physics is the Laplace transform. Given a function f(t), the Laplace transform is a new function F(s) defined by
\(F(s)=\int_{0}^{\infty} e^{-s t} f(t) \ d t\),
where we assume then s is a positive real number. For example, to find the Laplace transform oj f(t)= e?t, the following improper integral is evaluated using integration by parts:
\(F(s)=\int_{0}^{\infty} e^{-s t} e^{-t} \ d t=\int_{0}^{\infty} e^{-(s+1) t} \ d t=\frac{1}{s+1}\)
Verify the following Laplace transforms, where a is a real number.
\(f(t)=\sin \ a t \quad \ \rightarrow \quad \ F(s)=\frac{a}{s^{2}+a^{2}}\)
Questions & Answers
QUESTION:
Laplace transforms A powerful tool in solving problems in engineering and physics is the Laplace transform. Given a function f(t), the Laplace transform is a new function F(s) defined by
\(F(s)=\int_{0}^{\infty} e^{-s t} f(t) \ d t\),
where we assume then s is a positive real number. For example, to find the Laplace transform oj f(t)= e?t, the following improper integral is evaluated using integration by parts:
\(F(s)=\int_{0}^{\infty} e^{-s t} e^{-t} \ d t=\int_{0}^{\infty} e^{-(s+1) t} \ d t=\frac{1}{s+1}\)
Verify the following Laplace transforms, where a is a real number.
\(f(t)=\sin \ a t \quad \ \rightarrow \quad \ F(s)=\frac{a}{s^{2}+a^{2}}\)
ANSWER:Step 1 of 3
In this problem we have to verify the given laplace transform.
That is we have to prove : where a is a real number.
The laplace transform of a function is defined as follows.
Given a function f(t), the Laplace transform is a new function F(s) defined by where we assume s is a positive real number.