A high-speed drill rotating ccw at 2400 rpm comes to a

Chapter 4, Problem 65P

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QUESTION:

Problem 65P

A high-speed drill rotating ccw at 2400 rpm comes to a halt in 2.5 s.

a. What is the drill’s angular acceleration?

b. How many revolutions does it make as it stops?

Questions & Answers

QUESTION:

Problem 65P

A high-speed drill rotating ccw at 2400 rpm comes to a halt in 2.5 s.

a. What is the drill’s angular acceleration?

b. How many revolutions does it make as it stops?

ANSWER:

Step 1 of 3

Part (a)

Our aim is to find the angular acceleration of the high-speed drill which is rotating in a counterclockwise direction.

The initial angular speed \(\omega_{0}=2400 \mathrm{rpm}=40 \mathrm{rev} / \mathrm{s}\)

The final speed \(\omega_{f}=0\)

The time taken to halt \(\Delta \mathrm{t}=2.5 \mathrm{~s}\)

 

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