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A high-speed drill rotating ccw at 2400 rpm comes to a
Chapter 4, Problem 65P(choose chapter or problem)
QUESTION:
Problem 65P
A high-speed drill rotating ccw at 2400 rpm comes to a halt in 2.5 s.
a. What is the drill’s angular acceleration?
b. How many revolutions does it make as it stops?
Questions & Answers
QUESTION:
Problem 65P
A high-speed drill rotating ccw at 2400 rpm comes to a halt in 2.5 s.
a. What is the drill’s angular acceleration?
b. How many revolutions does it make as it stops?
ANSWER:
Step 1 of 3
Part (a)
Our aim is to find the angular acceleration of the high-speed drill which is rotating in a counterclockwise direction.
The initial angular speed \(\omega_{0}=2400 \mathrm{rpm}=40 \mathrm{rev} / \mathrm{s}\)
The final speed \(\omega_{f}=0\)
The time taken to halt \(\Delta \mathrm{t}=2.5 \mathrm{~s}\)