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Metabolizing 1.0 Kg of fat results in about 3.7*107 J of
Chapter 22, Problem 66GP(choose chapter or problem)
Problem 66GP
Metabolizing 1.0 Kg of fat results in about 3.7*107 J of internal energy in the body, (a) In one day, how much fat does the body burn to maintain the body temperature of a person staying in bed and metabolizing at an average rate of 95 W? (b) How long would it take to burn 1.0 kg of fat this way assuming there is no food intake?
Questions & Answers
QUESTION:
Problem 66GP
Metabolizing 1.0 Kg of fat results in about 3.7*107 J of internal energy in the body, (a) In one day, how much fat does the body burn to maintain the body temperature of a person staying in bed and metabolizing at an average rate of 95 W? (b) How long would it take to burn 1.0 kg of fat this way assuming there is no food intake?
ANSWER:
Solution 66GP
We are given energy required to burn off fat, power a person spends while staying in bed. Energy required by a person staying in bed for a day = power he spends * duration of day in seconds. We know Energy required to burn a kilo of fat. Knowing energy a man spends in a day we can calculate the amount of fat required.
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