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Solved: In a photocell, ultraviolet (UV) light provides
Chapter 23, Problem 71GP(choose chapter or problem)
In a photocell, ultraviolet (UV) light provides enough energy to some electrons in barium metal to eject them from the surface at high speed. See Fig. 17-33. To measure the maximum energy of the electrons, another plate above the barium surface is kept at a negative enough potential that the emitted electrons are slowed down and stopped, and return to the barium surface. If the plate voltage is -3.02 V (compared to the barium) when the fastest electrons are stopped, what was the speed of these electrons when they were emitted?
Questions & Answers
QUESTION:
In a photocell, ultraviolet (UV) light provides enough energy to some electrons in barium metal to eject them from the surface at high speed. See Fig. 17-33. To measure the maximum energy of the electrons, another plate above the barium surface is kept at a negative enough potential that the emitted electrons are slowed down and stopped, and return to the barium surface. If the plate voltage is -3.02 V (compared to the barium) when the fastest electrons are stopped, what was the speed of these electrons when they were emitted?
ANSWER:
Step-by-step solution
Step 1 of 3
The electrons are broken from the barium surface by the ultraviolet light. The kinetic energy of the electrons when they are broken from the barium. The ejected electrons are decelerated and stopped by the negative charged plate placed over the barium. We are going to find the speed of the ejected electrons when