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The vector called the position vector points from the

University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

Problem 102CP Chapter 1

University Physics | 13th Edition

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University Physics | 13th Edition | ISBN: 9780321675460 | Authors: Hugh D. Young, Roger A. Freedman

University Physics | 13th Edition

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Problem 102CP

The vector called the ?position vector points from the origin (0, 0, 0) to an arbitrary point in space with coordinates (?x?, ?y?, z?). Use what you know about vectors to prove the following: All points (?x?, ?y?, ?z?) that satisfy the equation ?Ax + ?By + ?Cz = 0, where ?A?, ?B?, and ?C are constants, lie in a plane that passes through the origin and that is perpendicular to the vector . Sketch this vector and the plane.

Step-by-Step Solution:

Solution 102CP Step 1: Given Position vector r = xi + yj + zk ˆ r starts from (0,0,0) and ends at (x,y,z) Step 2: ˆ ˆ ˆ Consider a vector S = Ai + Bj + Ck

Step 3 of 4

Chapter 1, Problem 102CP is Solved
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Textbook: University Physics
Edition: 13
Author: Hugh D. Young, Roger A. Freedman
ISBN: 9780321675460

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