For the vectors in Fig. E1.28, (a) Find the magnitude and direction of the vector product (b) find the magnitude and direction of

Solution 49E Part 1: Here the magnitudes of the vectors are, | | 8 m | | 10 m. The angle between these two vectors is, 0 0 0 0 90 + (90 53 ) = 127 . The cross product of these vectors will be, 0 A × D = A| || | = A D| || |27 = 8 × 10 × 0.972 = 77.81 CONCLUSION: So, the magnitude of A × D is 77.81 meters . The direction is going into the page....