For the two vectors . In Fig E1.43, (a) find the scalar product (b) find the magnitude and direction of the vector product

Solution 51E (a).scalar product A.B = AB cos A.B = (3.60 cm)(2.4 cm)cos (220 ) 0 A.B = 6.6186 (b).|a × b|= a.b sin = cos tan = 1 Angle b/w vector product always lies between /4 to 5/4. vector product A × B = AB sin A × B = (3.60 cm)(2.4 cm)sin (220 ) 0 A × B = 5.5529 Direction:here direction is perpendicular to the page.it will found by right-hand-rule.