Projectile Motion: Speed, Height, Time & Range

Chapter 3, Problem 27

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QUESTION:

A projectile is fired with an initial speed of 36.6 m/s at an angle of \(42.2^{\circ}\) above the horizontal on a long flat firing range. Determine

(a) the maximum height reached by the projectile,

(b) the total time in the air,

(c) the total horizontal distance covered (that is, the range), and

(d) the speed of the projectile 1.50 s after firing.

Questions & Answers

QUESTION:

A projectile is fired with an initial speed of 36.6 m/s at an angle of \(42.2^{\circ}\) above the horizontal on a long flat firing range. Determine

(a) the maximum height reached by the projectile,

(b) the total time in the air,

(c) the total horizontal distance covered (that is, the range), and

(d) the speed of the projectile 1.50 s after firing.

ANSWER:

Step 1 of 5

Part (a)

The relation of maximum height of the projectile is,

\(h=\frac{v_{1}^{2}-v_{2}^{2}}{2 g}\)

Here, \(v_{1}\) is the velocity of the projectile at maximum height whose value is zero and \(v_{2}\) is the vertical velocity of the projectile whose value is \(v_{2}=v \sin \theta\) and g is the acceleration due to gravity.

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Projectile Motion: Speed, Height, Time & Range
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Join us for an engaging exploration of projectile motion as we dissect a fascinating scenario. We delve into the physics of a projectile fired with an initial speed of 36.6 m/s at an angle of 42.2° above the horizontal on a flat firing range. Discover how to determine the maximum height, total time in the air, total horizontal distance covered (range), and the speed of the projectile 1.50 seconds after firing. This video will demystify the dynamics of projectiles in a clear and educational manne


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