(III) An electron (mass m = 9.11 X 10-31 kg) is
Chapter 16, Problem 36P(choose chapter or problem)
(III) An electron (mass \(m=9.11 \times 10^{-31} k g\) ) is acceler-ated in the uniform field \(\vec{E}\) \(\left(E=1.45 \times 10^{4} N / C\right)\) between two thin parallel charged plates. The separation of the plates is . The electron is accelerated from rest near the negative plate and passes through a tiny hole in the positive plate, Fig. 16-61. (a) With what speed does it leave the hole? (b) Show that the gravitational force can be ignored.
Equation transcription:
Text transcription:
m=9.11 times 10^{-31} k g
vec{E}
(E=1.45 times 10^{4} N / C)
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