Explain, without using a truth table, is true when p ,q,

Chapter 1, Problem 40E

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QUESTION:

Explain, without using a truth table, why \((p \vee \neg q) \wedge\) \)(q \vee \neg r) \wedge(r \vee \neg p)\) is true when \(p, q\), and \(r\) have the same truth value and it is false otherwise.

Equation Transcription:

Text Transcription:

(p vee neg q) wedge (q vee neg r) wedge (r vee  neg p)  

p,q  

r

Questions & Answers

QUESTION:

Explain, without using a truth table, why \((p \vee \neg q) \wedge\) \)(q \vee \neg r) \wedge(r \vee \neg p)\) is true when \(p, q\), and \(r\) have the same truth value and it is false otherwise.

Equation Transcription:

Text Transcription:

(p vee neg q) wedge (q vee neg r) wedge (r vee  neg p)  

p,q  

r

ANSWER:

Solution:

 Step 1:

  In this problem we need to explain without  using a truth table , is true when p,q and r have the same truth value and it is false otherwise.

  Given: is true. When p , q, and r have the same truth value  and it is false otherwise.

 Conjunction : If p and q are statements , then the statement  (read p and q)  is true  only when both p and q are true , and is false otherwise.

 Disjunction:  If p and q are statements , then the statement (read p or q)  is true  when at least  one of the two statements  is true , and is false when both are false.

Negation:Let P stand for a given statement.Thenrepresents the logical opposite of P. When P is true, then  is false and vice versa.

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