Solved: A pi meson of mass
Chapter 26, Problem 74GP(choose chapter or problem)
A pi meson of mass \(m_{\pi}\) decays at rest into a muon (mass \(m_{\pi}\) ) and a neutrino of negligible or zero mass. Show that the kinetic energy of the muon is
\(K E_{\mu}=\left(m_{\pi}-m_{\mu}\right)^{2} c^{2} /\left(2 m_{\pi}\right)\).
Equation Transcription:
Text Transcription:
m_\pi
m_\pi
K E_\mu=(m_\pi-m_\mu)^2 c^2 (2 m_\pi)
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